Efficient way to multiply with 7 | GeeksforGeeks

Efficient way to multiply with 7 We can multiply a number by 7 using bitwise operator. First left shift the number by 3 bits (you will get 8n) then subtract the original numberfrom the shifted number and return the difference (8n – n). Program: # include int multiplyBySeven(unsigned int n) { /* Note the inner bracket here. This is needed because precedence of '-' operator is higher than '<<' */ return ((n<<3) - n); } /* Driver program to test above function */ int main() { unsigned int n = 4; printf("%u", multiplyBySeven(n)); getchar(); return 0; } Time Complexity:

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