Codeforces - 363B. Fence & 466C. Number of Ways - zxzxzx0119的博客 - CSDN博客



Codeforces - 363B. Fence & 466C. Number of Ways - zxzxzx0119的博客 - CSDN博客

  • 先求前k个数的和，然后类似和滑动窗口一样；
  • 用两个指针，第一个i指向窗口的左边，另一个j指向窗口的右边，然后每次左边去掉一个数，右边加上一个数，然后计算新的和，看是否更小，如果更小，更新即可；

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