Codeforces 873D. Merge Sort 分治 + 构造 - WA是一笔财富 - CSDN博客



Codeforces 873D. Merge Sort 分治 + 构造 - WA是一笔财富 - CSDN博客

题意:给出一种特殊的归并排序,分治的方法同普通的归并排序一样,只是如果当前待排序的区间已经是有序的,就不会再继续递归了,让你构造一个会调用k次mergesort函数的序列。

思路:因为我们上来就会调用一次mergesort函数,并且只要当前待排序区间不是有序的,那么在该层递归里就会调用两次mergesort,因此可以推出总调用次数一定是个奇数。然后我们递归的构造答案序列(令答案序列初始有序),若k > 2, 我们就将当前区间的a[mid]和a[mid - 1]交换一下,这样可以保证下一层递归传进去的区间一定是个有序区间,这不会样影响k==1时候的退出(按照题给定义,必须当前区间有序才能退出)。交换后k就少了2,一直这样递归构造,出口就是l + 1 == r或者k == 1.


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