LeetCode - Pascal's Triangle | Darren's Blog



Given numRows, generate the first numRows of Pascal's triangle.
Each list p is generated by its previous list q . Except for the first and the last element,p[i]=q[i1]+q[i]
public List<List<Integer>> generate(int numRows) {
        List<List<Integer>> result = new ArrayList<List<Integer>>();
        if (numRows == 0)
            return result;
 
        // Generate the first list
        List<Integer> previous = new ArrayList<Integer>(1);
        previous.add(1);
        result.add(previous);
 
        // A new list is generated base on its previous list
        for (int i = 2; i <= numRows; i++) {
            List<Integer> current = new ArrayList<Integer>(i);
            current.add(1);
            for (int j = 1; j < previous.size(); j++)
                current.add(previous.get(j-1) + previous.get(j));
            current.add(1);
            result.add(current);
            previous = current;
        }
 
        return result;
    }
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