Reverse Integer leetcode | easycpp

Reverse digits of an integer.

class Solution { public:     int reverse(int x) {          int result = 0;          while(x != 0){              result = result * 10 + x % 10;              x = x / 10;          }          return result;     } };

The main idea below is to get all the digits of an integer. Just starting from last one.

while(x != 0){              int element = x % 10;              x = x / 10;          }

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