Codeforces Round #318 [RussianCodeCup Thanks-Round] (Div. 2) C. Bear and Poker | 书脊



Codeforces Round #318 [RussianCodeCup Thanks-Round] (Div. 2) C. Bear and Poker | 书脊

Codeforces Round #318 [RussianCodeCup Thanks-Round] (Div. 2) C. Bear and Poker

原题: http://codeforces.com/contest/574/problem/C

题目大意: 给一个n个数的数组, 问这几个数能不能通过double或者triple得到一个相同的数.

分析: 几个数能通过double或者triple得到一个相同的数, 必然这几个数由2 或者(和) 3的倍数组成, 所以这几个数可以分解成2^a*3^b* rest, 所以我们先要把每个数的2的倍数和3的倍数都消去, 然后检查rest部分是不是相同, 即可判断是不是可以通过double和triple组成相同的数.


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